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X^2+2.25X-240=0
a = 1; b = 2.25; c = -240;
Δ = b2-4ac
Δ = 2.252-4·1·(-240)
Δ = 965.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.25)-\sqrt{965.0625}}{2*1}=\frac{-2.25-\sqrt{965.0625}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.25)+\sqrt{965.0625}}{2*1}=\frac{-2.25+\sqrt{965.0625}}{2} $
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